(a-2/5)/(25a^2-4)/(5a)

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Solution for (a-2/5)/(25a^2-4)/(5a) equation: 


D( a )

5*a = 0

25*a^2-4 = 0

5*a = 0

5*a = 0

5*a = 0 // : 5

a = 0

25*a^2-4 = 0

25*a^2-4 = 0

25*a^2 = 4 // : 25

a^2 = 4/25

a^2 = 4/25 // ^ 1/2

abs(a) = 2/5

a = 2/5 or a = -2/5

a in (-oo:-2/5) U (-2/5:0) U (0:2/5) U (2/5:+oo)

((a-(2/5))/(25*a^2-4))/(5*a) = 0

((a-2/5)/(25*a^2-4))/(5*a) = 0

(a-2/5)/(5*a*(25*a^2-4)) = 0

a-2/5 = 0 // + 2/5

a = 2/5

a in { 2/5} 

a belongs to the empty set

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